x^2+10x-350=0

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Solution for x^2+10x-350=0 equation:



x^2+10x-350=0
a = 1; b = 10; c = -350;
Δ = b2-4ac
Δ = 102-4·1·(-350)
Δ = 1500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1500}=\sqrt{100*15}=\sqrt{100}*\sqrt{15}=10\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{15}}{2*1}=\frac{-10-10\sqrt{15}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{15}}{2*1}=\frac{-10+10\sqrt{15}}{2} $

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